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Xunor the enigmatic
A classical riddle
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Suggestion from M.theMoon the 09/19/02 :
You turn up both hourglasses, when the 4min one is empty you put the other one horizontaly = 4min and 3min
You repeat while passing the 3 remaining minutes and while you put the 4mn one horizontaly when the 3min are elasped = 1min and 7min
You start again while passing the minute = 4min and 6min
and once again = 4min and 2min
and (because you're not stingy) a last time = 2min and 7min
So and then, because you aren't bloody stupid, you do flowing one after the other...
Very tortuous, difficult to understand and don't answer the question

Suggestion from Azaroth the 09/27/02 :
It's almost: [7x(7+7+7+7+7)] - [(7+4+7+4+7+4)]= 42-33= 9
accepting, of course, that we can use negative times, but the miracles of modern science...
Nonsenses !

Suggestion from Azaroth the 09/27/02 :
I turn up the 7 minutes hourglass, then put horizontaly the 4 minutes one... but I don't think so
You are right to don't think so...

Suggestion from Lilou the 09/28/02 :
Firstly you isolate one minute of the 7 minutes hourglass this way:

1. You turn up both hourglasses at the same time
=> When the 4 mn hourglass is empty you have: (eslaped time: 4mn)
- the 4 min hourglass split this way: 0/4
- the 7 min hourglass split this way: 3/4
2. You do flowing the 4 min hourglass and the 7 min hourglass' 3 min at the same time We turn up the 4 min hourglass
=> You have:
- the 4 min hourglass: 1/3
- the 7 min hourglass: 0/7
3. You do flowing the 7 min hourglass and the remaining minute of the 4 min hourglass
=> You have:
- the 4 min hourglass: 1/7
- the 7 min hourglass: 0/4

Now, you can time 9 min:
you will flown 2 times the 4 minutes hourglass (2*4) + the isolated minute in the 7 min hourglass

This answer is interesting, but not acceptable, because we can start whan the leader decide

Suggestion from Teva de Tahiti the 09/29/02 :
He startes both hourglasses at the same time,
when the 4 min hourglass is empty he give the starting signal of the 9 minutes,
at this instant 3 minutes remain in the 7mn hourglass.
When these three minutes are finished
he just have to turn up the 7 minutes hourglass
to have 9 minutes when it's empty.
This is an answer doubly false, indeed:
- we time 10 mn (3+7=10 and not 9 !!!)
- and we don't start without any preparation

Return to the terms of this riddle.

Last edit for this page: 12/26/2008 (03h34pm)